“In any Electrical Network, the algebraic sum of the
currents meeting at a point or a junction is equal to zero”.
In Simple words it means that the total amount of current
leaving a junction is equal to the total amount of the current entering the
same junction.This is because of that there is no accumulation of charge at the
junction of the network. Kirchhoff current law is also called a Kirchhoff Point Law and junction rule.
Assume that some conductors meeting at a point A as shown in
figure 1(a).Some conductors having
currents leading to the point A and some have currents that are leading away
from point A.Now Assume that the incoming currents are positive and the
outgoing currents are negative,Then we have :
Incoming Currents = Outgoing Currents
Similarly in
Figure1(b) for node A
Thus the result is
KCL With the Help of Example:
Example
2.14. In
the network of Fig. 2, the different currents and voltages are as under :
i2 = 5e−2t, i4 = 3 sin t and v3 = 4e −2t
Using KCL, find voltage v1.
Solution. According to KCL, the algebraic sum of the currents meeting at juncion A is zero i.e.
i1 + i2 + i3 + (−i4) = 0
i1 + i2 + i3 −i4 = 0 ….(1)
Now, current through a capacitor is given by i = C dv/d
Substituting
this value in Eq (1) above, we get
i1 + 5e−2t −16e−2t −3 sin t = 0
or i1 = 3 sin t +
11e−2t
The voltage v1 developed across the coil is:
V1=L.di1=4. di1 (3 sin t +11e− 2t)
dt dt
V1
= 4 (3 cos t −22e−2t) =
12 cos t −88e−2t